AP EAMCET · Maths · Probability
Two bolts, two nuts and three needles are in a box. Two parts are choosen at random from the box. What is the probability that one is a
bolt and one is a needle?
- A \(\frac{2}{21}\)
- B \(\frac{4}{21}\)
- C \(\frac{6}{21}\)
- D \(\frac{12}{21}\)
Answer & Solution
Correct Answer
(C) \(\frac{6}{21}\)
Step-by-step Solution
Detailed explanation
2 Bolts, 2 Nuts, 3 Needles Total number of possible outcomes, when we choose 2 parts \(n(S)={ }^7 C_2=\frac{7 \times 6}{1 \times 2}=21\) Let E be the event that the parts drawn are bolt and needle.…
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