AP EAMCET · Maths · Probability
Three unbiased coins are tossed. Then, the probability of getting at most two heads is
- A \(3 / 4\)
- B \(1 / 4\)
- C \(3 / 8\)
- D \(7 / 8\)
Answer & Solution
Correct Answer
(D) \(7 / 8\)
Step-by-step Solution
Detailed explanation
3 unbiased coins are tossed. Sample space, \(S=\{\) HHH, HHT, HTH, HTT, THH, THT, TTH, TTT \(\}\) \(n(S)=8\) Let \(E\) be the event of getting at most two heads. \(\Rightarrow E^{\prime}=\{\mathrm{HHH}\}\)…
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