AP EAMCET · Maths · Vector Algebra
Three non-zero non-collinear vectors \(\hat{\mathbf{a}}, \mathbf{b}\) and \(\hat{\mathbf{c}}\) are such that \(\hat{\mathbf{a}}+3 \hat{\mathbf{b}}\) is collinear with \(\hat{\mathbf{c}}\), while \(\hat{\mathbf{c}}\) is \(3 \hat{\mathbf{b}}+2 \hat{\mathbf{c}}\) collinear with \(\hat{\mathbf{a}}\). Then \(\hat{\mathbf{a}}+3 \hat{\mathbf{b}}+2 \hat{\mathbf{c}}\) equals to
- A \(0\)
- B \(2 \hat{\mathbf{a}}\)
- C \(3 \hat{\mathbf{b}}\)
- D \(4 \hat{\mathbf{c}}\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
Given, \(\mathbf{a}+3 \mathbf{b}\) is collinear with c. \[ \begin{array}{rrr} \therefore & a+3 b=\lambda c \\ \text { or } & a+3 b-\lambda c=0 \end{array} \] And \(3 \mathbf{b}+2 \mathbf{c}\) is collinear with \(\mathbf{a}\).…
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