ExamBro
ExamBro
AP EAMCET · Maths · Permutation Combination

There are 10 points on the line \(A B\) excluding \(A\) and \(B\) and 8 points on \(A C\) excluding \(A\) and \(C\). Number of triangles formed with these points not considering \(A, B\) and \(C\) is

  1. A \({ }^{18} C_3-{ }^{10} C_3\)
  2. B \(360\)
  3. C \(640\)
  4. D \(280\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(640\)

Step-by-step Solution

Detailed explanation

There are 10 point on \(A B\) and 8 point on \(A C\). \(\therefore\) Total number of triangle formed is \(\begin{aligned} & { }^{18} C_3-{ }^{10} C_3-{ }^8 C_3 \\ & =816-120-56=640\end{aligned}\)