AP EAMCET · Maths · Circle
The triangle \(P Q R\) is inscribed in the circle \(x^2+y^2=25\). If \(\mathrm{Q}=(3,4)\) and \(\mathrm{R}=(-4,3)\) then \(\angle \mathrm{QPR}=\)
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{\pi}{4}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
The given equation of circle is \(x^2+y^2=25\) \(\therefore\) Centre is \((0,0)\) and \(r=5\) Now, QR \(\begin{aligned} & =\sqrt{(-4-3)^2+(3-4)^2}=5 \sqrt{2} \\ & O Q=O R=5 \end{aligned}\)…
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