AP EAMCET · Maths · Differentiation
If \(y=\tan (\log x)\), then \(\frac{d^2 y}{d x^2}=\)
- A \(\frac{-\sec ^2(\log x)[1+2 \tan x]}{x^2}\)
- B \(\frac{\sec ^2(\log x)[1+\tan (\log x)]}{x^2}\)
- C \(\frac{\sec (\log x)[2+\tan (\log x)-1]}{x^2}\)
- D \(\frac{\sec ^2(\log x)[2+\tan (\log x)-1]}{x^2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sec ^2(\log x)[2+\tan (\log x)-1]}{x^2}\)
Step-by-step Solution
Detailed explanation
\(y=\tan (\log x)\) \(\frac{d y}{d x}=\frac{\sec ^2(\log x)}{x}\) \(\frac{d^2 y}{d x^2}=\frac{2 \sec ^2(\log x) \tan (\log x)}{x^2}-\frac{\sec ^2(\log x)}{x^2}\) \(=\frac{\sec ^2(\log x)}{x^2}[2+\tan (\log x)-1]\)
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