AP EAMCET · Maths · Circle
The sum of the minimum and maximum distance of the point \((4,-3)\) to the circle \(x^2+y^2+4 x-10 y-7=0\), is
- A \(10\)
- B \(12\)
- C \(16\)
- D \(20\)
Answer & Solution
Correct Answer
(D) \(20\)
Step-by-step Solution
Detailed explanation
Let the given point be \(P(4,-3)\) and the given circle is \(x^2+y^2+4 x-10 y-7=0\) Centre of circle \(=\mathrm{C}(-2,5)\) \(\text { Radius }=\sqrt{(-2)^2+(5)^2+7}\) \(=\sqrt{4+25+7}=\sqrt{36}=6\) Maximum distance, \(a=C P+r\) Minimum distance, \(b=C P-r\) Sum of the maximum and…
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