AP EAMCET · Maths · Probability
A bag contains 21 toys numbered 1 to 21 . A toy is drawn and then another toy is drawn without replacement. The probability that both toys will show even numbers is
- A \(\frac{5}{21}\)
- B \(\frac{3}{14}\)
- C \(\frac{11}{42}\)
- D \(\frac{4}{21}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{14}\)
Step-by-step Solution
Detailed explanation
Total number of toys numbered from 1 to 21 . \[ \mathrm{P} \text { (two toys will show even numbers) }==\frac{{ }^{10} \mathrm{c}_2}{{ }^{21} \mathrm{c}_2} \] The total number of even numbers between 1 to 21 is 10.…
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