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AP EAMCET · Maths · Functions

The range of the real valued function fx=x2+2x+8x2+2x+4 is

  1. A 73,
  2. B 0,
  3. C 1,
  4. D 1,73
Verified Solution

Answer & Solution

Correct Answer

(D) 1,73

Step-by-step Solution

Detailed explanation

Given fx=x2+2x+8x2+2x+4 =1+4x2+2x+4=1+4x+12+3 We know, 3≤x+12+3<∞ ⇒0<4x+12+3≤43⇒1<1+4x+12+3≤73 ⇒1<1+4x+12+3≤73 Hence, range of fx will be (1,73]
From AP EAMCET
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