AP EAMCET · Maths · Circle
The product of the slopes of the common tangents drawn to the circles \(x^2+y^2+2 x-2 y-2=0\) and \(x^2+y^2-2 x+\)
- A \(-1\)
- B \(3\)
- C \(\frac{-8}{3}\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
Let \(S_1: x^2+y^2+2 x-2 y-2=0\) \(\begin{aligned} & C_1 \equiv(-1,1) \text { and } r_1=\sqrt{1+1+2}=2 \\ & S_2: x^2+y^2-2 x+2 y+1=0 \\ & C_2 \equiv(1,-1) \text { and } r_2=\sqrt{1+1-1}=1\end{aligned}\)…
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