AP EAMCET · Maths · Probability
The probability distribution of a random variable X is given below
| X | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| \(\mathrm{P}\left(\mathrm{X}=\mathrm{x}_{\mathrm{i}}\right)\) | \(\alpha\) | \(\alpha\) | \(\alpha\) | \(\beta\) | \(\beta\) | 0.3 |
If \(\mu\) and \(\sigma^2\) represent the mean and variance of X and \(\mu=4.2\), then \(\sigma^2+\mu^2=\)
- A 20.4
- B 10.8
- C 16.4
- D 21.4
Answer & Solution
Correct Answer
(A) 20.4
Step-by-step Solution
Detailed explanation
\(3\alpha + 2\beta + 0.3 = 1 \implies 3\alpha + 2\beta = 0.7\) \(1\alpha + 2\alpha + 3\alpha + 4\beta + 5\beta + 6(0.3) = 4.2 \implies 6\alpha + 9\beta + 1.8 = 4.2 \implies 6\alpha + 9\beta = 2.4 \implies 2\alpha + 3\beta = 0.8\) \(\alpha = 0.1, \beta = 0.2\)…
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