AP EAMCET · Maths · Permutation Combination
The number of ways of arranging 9 men and 5 women around a circular table so that no two women come together are
- A \(8!^8 P_5\)
- B \(9!{ }^9 P_5\)
- C \(8!{ }^9 P_5\)
- D \(8!5\) !
Answer & Solution
Correct Answer
(C) \(8!{ }^9 P_5\)
Step-by-step Solution
Detailed explanation
First fix the men in circular arrangement, which can be done in \((9-1)!=8\) ! ways Now, there are 9 places between the men and 5 womens to be seated between the men. That can be done in \({ }^9 \mathrm{P}_5\) ways. \(\therefore\) Total no. of ways to sit…
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