AP EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Which of the following represents correct order of oxidising power of halogens with water?
- A \(\mathrm{I}_2>\mathrm{Br}_2>\mathrm{Cl}_2>\mathrm{F}_2\)
- B \(\mathrm{Cl}_2>\mathrm{F}_2>\mathrm{Br}_2>\mathrm{I}_2\)
- C \(\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{I}_2>\mathrm{Br}_2\)
- D \(\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2\)
Step-by-step Solution
Detailed explanation
Whenever one of the halogens is involved in oxidising a species in solution, the halogen is reduced to a halide ion associated with water molecules. The following reactions illustrate this process \({ }^{\circ}\) \(\mathrm{F}_2(g)+2 e^{-} \longrightarrow 2 \mathrm{~F}^{-}(a q)\)…
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