AP EAMCET · Maths · Permutation Combination
The number of ways of arranging 2 red. 3 white and 5 yellow roses of different sizes into a garland such that no two yellow roses come together is
- A 2880
- B 144
- C 1440
- D 288
Answer & Solution
Correct Answer
(C) 1440
Step-by-step Solution
Detailed explanation
Given 2 Red, 3 White and 5 Yellow roses. \(\Rightarrow \text { Total }=10 \text { roses }\) \(\because\) Number of ways of arranging 2 Red and 3 White roses \(=(5-1)!=4!\) So, required number of ways \(=\frac{4!\times 5!}{2}=\frac{24 \times 120}{2}=1440 .\)
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