AP EAMCET · Maths · Ellipse
The number of values of ' \(c\) ' for which the line \(y=4 x+c\) touches the ellipse \(\frac{x^2}{4}+\frac{y^2}{1}=1\) is
- A 0
- B 1
- C 2
- D Infinite
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
The possible value of ' \(c\) ' for which the line \(y=4 x+c\) touches the ellipse \(\frac{x^2}{4}+\frac{y^2}{1}=1\) is \(c= \pm \sqrt{4 \times 4+1}= \pm 3\)
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