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AP EAMCET · Maths · Trigonometric Equations

The number of ordered pairs \((x, 1)\) satisfying the equations \(\sin x+\sin y=\sin (x+y)\) and \(|x|+|y|=1\) is

  1. A \(2\)
  2. B \(3\)
  3. C \(4\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(6\)

Step-by-step Solution

Detailed explanation

\(\sin x+\sin y=\sin (x+y)\) \(2 \sin \frac{(x+y)}{2} \cos \frac{(x-y)}{2}=2 \sin \frac{(x+y)}{2} \cos \frac{(x+y)}{2}\) \(\Rightarrow \sin \frac{(x+y)}{2}\left[\cos \frac{(x-y)}{2}-\cos \frac{(x+y)}{2}\right]=0\)…