AP EAMCET · Maths · Binomial Theorem
The number of elements in the set \(\left\{x \in \mathbb{N}:^{20-2 x} c_{x-3} \in \mathbb{N}\right\}\) is
- A \(3\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
\(\because^{20-2 x} C_{x-3} \in N\) So, \(20-2 \mathrm{x}>0 \Rightarrow \mathrm{x} < 10\) and \(x-3 \geq 0 \Rightarrow x \geq 3\) and \(20-2 x \geq x-3 \Rightarrow x \leq \frac{23}{3}\) \(\Rightarrow \mathrm{x} \leq 7 \quad\{\because \mathrm{x} \in \mathrm{N}\}\) Now, from above…
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