AP EAMCET · Maths · Trigonometric Ratios & Identities
If \(A+B=\frac{\pi}{4}\), then \(\frac{\cos B-\sin B}{\cos B+\sin B}=\)
- A \(\sin A\)
- B \(\cos A\)
- C \(\tan A\)
- D \(\cot A\)
Answer & Solution
Correct Answer
(C) \(\tan A\)
Step-by-step Solution
Detailed explanation
\(\frac{\cos B-\sin B}{\cos B+\sin B} = \frac{1-\tan B}{1+\tan B}\) \(\frac{1-\tan B}{1+\tan B} = \tan(\frac{\pi}{4}-B)\) Given \(A+B=\frac{\pi}{4}\), so \(A=\frac{\pi}{4}-B\) \(\tan(\frac{\pi}{4}-B) = \tan A\)
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