AP EAMCET · Maths · Probability
The minimum number of times a fair coin needs to be tossed, so that the probability of getting at least two heads is at least 0.96 is
- A \(5\)
- B \(6\)
- C \(7\)
- D \(8\)
Answer & Solution
Correct Answer
(D) \(8\)
Step-by-step Solution
Detailed explanation
The probability of getting exactly 1 head in \(n\) toss \(=\frac{1}{2^n}\) the probability of getting exactly 1 head in \(\mathrm{n}\) toss \(=\frac{{ }^n C_1}{2^n}\) The probability of getting at least 2 head \(=1-\frac{n+1}{2^n}\) Now,…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(f(x) \in \mathbf{Q}[x]\) be a non-zero polynomial such that all its roots are irrational, then the degree of \(f(x)\) isAP EAMCET 2020 Easy
- The angle between the curve \(2 y=e^{-x / 2}\) and the \(y\)-axis is \(\tan ^{-1}(\mathrm{k})\) then \(\mathrm{k}=\)AP EAMCET 2022 Hard
- The maximum possible number of real roots of the equation \(x^{\frac{5}{5}}-6 x^2-4 x+5=0\) isAP EAMCET 2002 Medium
- If in a \(\triangle A B C, r_3=r_1+r_2+r\), then \(\angle A+\angle B\) is equal toAP EAMCET 2004 Medium
- If a Polynomial \(x^4+x^2+1\) is divisible by \(x^2+m x+1\) and \(x^2+n x+1\). Then \(m+n\) is equal to
(1) 2
(2) 0
(3) 3
(4) 4AP EAMCET 2020 Medium - In a \(\triangle A B C,(a+b+c)(b+c-a)=\lambda b c\), thenAP EAMCET 2015 Medium
More PYQs from AP EAMCET
- In nucleoside, the base is attached to which position of sugar molecule?AP EAMCET 2023 Medium
- The rate of dehydrohalogenation of which one among the following is less ?AP EAMCET 2018 Easy
- The number of integers between 10 and 10,000 such that in every integer every digit is greater than its immediate preceeding digit, isAP EAMCET 2025 Hard
- If the lines \(x^2+2 x y-35 y^2-4 x+44 y-12=0\) and \(5 x+k y-8=0\) are concurrent, then \(k\) equalsAP EAMCET 2021 Medium
- If \(\vec{a}, \vec{b}, \vec{c}\) are 3 vectors such that \(|\vec{a}|=5,|\vec{b}|=8,|\vec{c}|=11\) and \(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0}\) then the angle between the vectors \(\vec{a}\) and \(\vec{b}\) isAP EAMCET 2024 Easy
- Two students appeared simultaneously for an entrance exam. If the probability that the first student gets qualified in the exam is \(\frac{1}{4}\) and the probability that the second student gets qualified in the same exam is \(\frac{2}{5}\), then the probability that atleast one of them gets qualified in that exam isAP EAMCET 2025 Medium