AP EAMCET · Maths · Vector Algebra
If \(\vec{a}, \vec{b}, \vec{c}\) are 3 vectors such that \(|\vec{a}|=5,|\vec{b}|=8,|\vec{c}|=11\) and \(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0}\) then the angle between the vectors \(\vec{a}\) and \(\vec{b}\) is
- A \(\cos ^{-1} \frac{2}{5}\)
- B \(\cos ^{-1} \frac{10}{11}\)
- C \(\cos ^{-1} \frac{41}{55}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(A) \(\cos ^{-1} \frac{2}{5}\)
Step-by-step Solution
Detailed explanation
\(\vec{a}+\vec{b}+\vec{c}=\overrightarrow{0} \Rightarrow \vec{a}+\vec{b}=-\vec{c}\) Squaring both sides…
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