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AP EAMCET · Maths · Circle

If the shortest distance from \((2,-14)\) to the circle \(x^2+y^2+6 x+4 y-12=0\) is \(d\) and the length of the tangent drawn from the same point to the circle is \(l\), then \(\sqrt{d+l}=\)

  1. A 13
  2. B \(2 \sqrt{5}\)
  3. C 12
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \sqrt{5}\)

Step-by-step Solution

Detailed explanation

Given circle, \(x^2+y^2+6 x+4 y-12=0\) Here, centre is \(O(-3,-2)\) and radius \(=\sqrt{9+4+12}=\sqrt{25}=5\) Shortest distance of the point \(P(2,-14)\) to the circle is…