AP EAMCET · Maths · Circle
The length of the common chord of the circles \(x^2+y^2+3 x+5 y+4=0\) and \(x^2+y^2+5 x+3 y+4=0\) is
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
Equation of common chord: \((x^2+y^2+3x+5y+4) - (x^2+y^2+5x+3y+4) = 0 \Rightarrow -2x+2y=0 \Rightarrow x-y=0\) For circle \(x^2+y^2+3x+5y+4=0\): Center \(C=(-3/2, -5/2)\), Radius \(R = \sqrt{(3/2)^2+(5/2)^2-4} = \sqrt{9/4+25/4-16/4} = \sqrt{18/4} = 3/\sqrt{2}\) Distance from…
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