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AP EAMCET · Maths · Circle

The length of the chord joining points \((4 \cos \theta, 4 \sin \theta)\) and \(\left[4 \cos \left(\theta+60^{\circ}\right)\right.\), \(\left.4 \sin \left(\theta+60^{\circ}\right)\right]\) on the circle \(x^2+y^2=16\) is

  1. A 4
  2. B 8
  3. C 16
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) 4

Step-by-step Solution

Detailed explanation

Given, equation of circle \(x^2+y^2=16\) Points are \((4 \cos \theta, 4 \sin \theta)\) and \[ \left[4 \cos \left(\theta+60^{\circ}\right), 4 \sin \left(\theta+60^{\circ}\right)\right] \] Clearly \(\triangle O A B\) is an equilateral triangle.…
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