AP EAMCET · Maths · Circle
The length of the chord joining points \((4 \cos \theta, 4 \sin \theta)\) and \(\left[4 \cos \left(\theta+60^{\circ}\right)\right.\), \(\left.4 \sin \left(\theta+60^{\circ}\right)\right]\) on the circle \(x^2+y^2=16\) is
- A 4
- B 8
- C 16
- D 2
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Given, equation of circle \(x^2+y^2=16\) Points are \((4 \cos \theta, 4 \sin \theta)\) and \[ \left[4 \cos \left(\theta+60^{\circ}\right), 4 \sin \left(\theta+60^{\circ}\right)\right] \] Clearly \(\triangle O A B\) is an equilateral triangle.…
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