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AP EAMCET · Maths · Functions

Let \(g(x)=1+x-[x]\) and \(f(x)= \begin{cases}-1, & x < 0 \\ 0, & x=0 \\ 1, & x>0\end{cases}\) \([x]\) denotes the greatest integer less than or equal to \(x\). Then for all \(\mathrm{x}, \mathrm{f}(\mathrm{g}(\mathrm{x}))=\)

  1. A \(1\)
  2. B x
  3. C \(f(x)\)
  4. D \(g(x)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(g(x) = 1 + x - [x] = 1 + \{x\}\) Since \(0 \le \{x\} \(g(x) > 0\) \(f(g(x)) = 1\)