AP EAMCET · Maths · Hyperbola
If \(e_1\) and \(e_2\) are the eccentricities of the hyperbola \(16 x^2-9 y^2=1\) and its conjugate respectively. Then, \(3 e_1=\)
- A \(5 e_2\)
- B \(4 e_2\)
- C \(2 e_2\)
- D \(e_2\)
Answer & Solution
Correct Answer
(B) \(4 e_2\)
Step-by-step Solution
Detailed explanation
Given, hyperbola is \(16 x^2-9 y^2=1\) \(\frac{x^2}{\frac{1}{16}}-\frac{y^2}{\frac{1}{9}}=1\) \(\Rightarrow \quad \frac{x^2}{\left(\frac{1}{4}\right)^2}-\frac{y^2}{\left(\frac{1}{3}\right)^2}=1\) We know that Eccentricity of a hyperbola, \(e_1^2=1+\frac{b^2}{a^2}\)…
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