AP EAMCET · Maths · Straight Lines
The family of lines, forming an isosceles triangle with the lines \(3 x-4 y-2=0\) and \(12 x-5 y+6=0\), is
- A \(9 \mathrm{x}+7 \mathrm{y}+\mathrm{c}=0\)
- B \(7 \mathrm{x}-9 \mathrm{y}+\mathrm{c}=0\)
- C \(9 x-7 y+c=0\)
- D \(x \pm y+c=0\)
Answer & Solution
Correct Answer
(C) \(9 x-7 y+c=0\)
Step-by-step Solution
Detailed explanation
We know that obtuse bisector of equal sides of a triangle is parallel to third side.…
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