ExamBro
ExamBro
AP EAMCET · Chemistry · Chemical Kinetics

The following graph is obtained for a first order reaction (A \(\rightarrow\) P). The activation energy ( \(\mathrm{E}_{\mathrm{a}}\) in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) and heat of reaction ( \(|\Delta \mathrm{H}|\) in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) for this reaction are respectively
\(\left(\mathrm{x}=\right.\) reaction coordinate \(; \mathrm{y}=\mathrm{E}\) in \(\left.\mathrm{kJ} \mathrm{mol}^{-1}\right)\)

  1. A 5,15
  2. B 15,5
  3. C 25,5
  4. D 10,25
Verified Solution

Answer & Solution

Correct Answer

(B) 15,5

Step-by-step Solution

Detailed explanation

\(E_a = E_{TS} - E_{Reactants}\) \(E_a = 25 - 10 = 15 \mathrm{kJ} \mathrm{mol}^{-1}\) \(\Delta H = E_{Products} - E_{Reactants}\) \(\Delta H = 5 - 10 = -5 \mathrm{kJ} \mathrm{mol}^{-1}\) \(|\Delta H| = |-5| = 5 \mathrm{kJ} \mathrm{mol}^{-1}\)