AP EAMCET · Chemistry · Chemical Kinetics
The following graph is obtained for a first order reaction (A \(\rightarrow\) P). The activation energy ( \(\mathrm{E}_{\mathrm{a}}\) in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) and heat of reaction ( \(|\Delta \mathrm{H}|\) in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) for this reaction are respectively
\(\left(\mathrm{x}=\right.\) reaction coordinate \(; \mathrm{y}=\mathrm{E}\) in \(\left.\mathrm{kJ} \mathrm{mol}^{-1}\right)\)

- A 5,15
- B 15,5
- C 25,5
- D 10,25
Answer & Solution
Correct Answer
(B) 15,5
Step-by-step Solution
Detailed explanation
\(E_a = E_{TS} - E_{Reactants}\) \(E_a = 25 - 10 = 15 \mathrm{kJ} \mathrm{mol}^{-1}\) \(\Delta H = E_{Products} - E_{Reactants}\) \(\Delta H = 5 - 10 = -5 \mathrm{kJ} \mathrm{mol}^{-1}\) \(|\Delta H| = |-5| = 5 \mathrm{kJ} \mathrm{mol}^{-1}\)
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