AP EAMCET · Maths · Straight Lines
The equation of the line through the point \((-1,3)\) in symmetrical form, when the angle made by the line with the positive direction of \(X\)-axis is \(120^{\circ}\), is given by
- A \(\frac{(x+1)}{-1 / 2}=\frac{(y-3)}{\sqrt{3} / 2}=r\)
- B \(\frac{(x+1)}{1 / 2}=\frac{(y+3)}{\sqrt{3} / 2}=r\)
- C \(\frac{(x+1)}{-1 / 2}=\frac{(y+3)}{\sqrt{3} / 2}=r\)
- D \(\frac{(x+1)}{1 / 2}=\frac{(y-3)}{\sqrt{3} / 2}=r\)
Answer & Solution
Correct Answer
(A) \(\frac{(x+1)}{-1 / 2}=\frac{(y-3)}{\sqrt{3} / 2}=r\)
Step-by-step Solution
Detailed explanation
The equation of line through the point \(\left(x_1, y_1\right)\) in symmetrical form, if it's inclination with positive direction of \(X\)-axis is \(\theta\) is \[ \frac{x-x_1}{\cos \theta}=\frac{y-y_1}{\sin \theta}=r \] So, the equation of the line in symmetric form where…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- The minimum value of \(\left(1+\frac{1}{\sin ^n \alpha}\right)\left(1+\frac{1}{\cos ^n \alpha}\right)\) isAP EAMCET 2022 Hard
- The tangents drawn to the hyperbola \(5 \mathrm{x}^2-9 \mathrm{y}^2=90\) through a variable point P make the angles \(\alpha\) and \(\beta\) with its transverse axis. If \(\alpha, \beta\) are the complementary angles, then the locus of P isAP EAMCET 2025 Medium
- If \(P_1, P_2, P_3\) are the perimeters of the three circles \(x^2+y^2+8 x-6 y=0\), \(4 x^2+4 y^2-4 x-12 y-186=0\) and \(x^2+y^2-6 x+6 y-9=0\) respectively, thenAP EAMCET 2004 Hard
- The values of \(m\) for which the line \(y=m x+2\) becomes a tangent to the hyperbola \(4 x^2-9 y^2=36\) isAP EAMCET 2016 Easy
- The substitution \(\frac{d y}{d x}=z\), reduces the differential equation \(\frac{d^2 y}{d x^2}-\frac{d y}{d x}=0\) to a differential equation whose solution is \(\mathrm{z}=\)AP EAMCET 2022 Medium
- If \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) are position vectors of the vertices of \(\triangle A B C\), then \(\frac{(\mathbf{a}-\mathbf{c}) \times(\mathbf{b}-\mathbf{a})}{(\mathbf{b}-\mathbf{a}) \cdot(\mathbf{c}-\mathbf{a})}=\)AP EAMCET 2020 Easy
More PYQs from AP EAMCET
- Given the circle \(C\) with the equation \(x^2+y^2-2 x+10 y-38=0\). Match the List I with the List II given below concerning \(C\)
The correct answer is
\(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D }\end{array}\)AP EAMCET 2012 Easy - \((1+\sqrt{5}+\mathrm{i} \sqrt{10-2 \sqrt{5}})^5=\)AP EAMCET 2025 Medium
- Identify the correct statements
I) CO reduces the oxygen carrying ability of blood
II) Producer gas contains \(\mathrm{CO} ~\&~ \mathrm{~N}_2\)
III) C -O bond length in \(\mathrm{CO}_2\) is 115 pmAP EAMCET 2025 Medium - If \(a=\cos \left(\frac{8 \pi}{11}\right)+i \sin \left(\frac{8 \pi}{11}\right)\), then \(\operatorname{Re}\left(a+a^2+a^3+a^4+a^5\right)=\)AP EAMCET 2018 Hard
- If slope of one line of \(a x^2+4 x y+y^2=0\) is 3 times the other, then the value of ' \(a\) ' isAP EAMCET 2020 Easy
- Find the equation of the circle which passes through origin and cuts off the intercepts and over the and axes respectively.AP EAMCET 2021 Easy