AP EAMCET · Maths · Vector Algebra
If \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) are position vectors of the vertices of \(\triangle A B C\), then \(\frac{(\mathbf{a}-\mathbf{c}) \times(\mathbf{b}-\mathbf{a})}{(\mathbf{b}-\mathbf{a}) \cdot(\mathbf{c}-\mathbf{a})}=\)
- A \(\cot C\)
- B \(\tan A\)
- C \(\tan C\)
- D \(-\tan A\)
Answer & Solution
Correct Answer
(B) \(\tan A\)
Step-by-step Solution
Detailed explanation
\[ \text { } \frac{(\mathbf{a}-\mathbf{c}) \times(\mathbf{b}-\mathbf{a})}{(\mathbf{b}-\mathbf{a}) \cdot(\mathbf{c}-\mathbf{a})}=\frac{\mathbf{C A} \times \mathbf{A B}}{\mathbf{A B} \cdot \mathbf{A C}} \] Hence, option (2) is correct.
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