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AP EAMCET · Maths · Vector Algebra

If \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) are position vectors of the vertices of \(\triangle A B C\), then \(\frac{(\mathbf{a}-\mathbf{c}) \times(\mathbf{b}-\mathbf{a})}{(\mathbf{b}-\mathbf{a}) \cdot(\mathbf{c}-\mathbf{a})}=\)

  1. A \(\cot C\)
  2. B \(\tan A\)
  3. C \(\tan C\)
  4. D \(-\tan A\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\tan A\)

Step-by-step Solution

Detailed explanation

\[ \text { } \frac{(\mathbf{a}-\mathbf{c}) \times(\mathbf{b}-\mathbf{a})}{(\mathbf{b}-\mathbf{a}) \cdot(\mathbf{c}-\mathbf{a})}=\frac{\mathbf{C A} \times \mathbf{A B}}{\mathbf{A B} \cdot \mathbf{A C}} \] Hence, option (2) is correct.