AP EAMCET · Maths · Circle
The equation of the circle whose diameter is the common chord of the circles \(x^2+y^2+2 x+3 y+1=0\) and \(x^2+y^2+4 x+3 y+2=0\) is
- A \(2 x^2+2 y^2+x+3 y+2=0\)
- B \(2 x^2+2 y^2+2 x+6 y+1=0\)
- C \(2 x^2+2 y^2+4 x-3 y-1=0\)
- D \(x^2+y^2+2 x+6 y-2=0\)
Answer & Solution
Correct Answer
(B) \(2 x^2+2 y^2+2 x+6 y+1=0\)
Step-by-step Solution
Detailed explanation
The equation of the common chord of the circles \(x^2+y^2+2 x+3 y+1=0\) and \(x^2+y^2+4 x+3 y+2=0\) is given by \[ 2 x+1=0 \quad \text { [using: } S_1-S_2=0 \text { ] } \] The equation of a circle passing through the intersection of the given circles is…
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