AP EAMCET · Maths · Circle
The equation of the circle whose diameter is the common chord of the circles \(x^2+y^2+2 x+2 y+1=0\) and \(x^2+y^2+4 x+6 y+4=0\) is
- A \(10 x^2+10 y^2+14 x+8 y+1=0\)
- B \(3 x^2+3 y^2-3 x+6 y-8=0\)
- C \(2 x^2+2 y^2-2 x+4 y+1=0\)
- D \(x^2+y^2-x+2 y+4=0\)
Answer & Solution
Correct Answer
(A) \(10 x^2+10 y^2+14 x+8 y+1=0\)
Step-by-step Solution
Detailed explanation
Given, \(S_1 \equiv x^2+y^2+2 x+2 y+1=0\) and \(S_2 \equiv x^2+y^2+4 x+6 y+4=0\) Now, the equation of common chord of these two circles. \(S_1-S_2=0\)…
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