AP EAMCET · Maths · Circle
The equation of circle passing through \((0,0)\) and cutting orthogonally the circles \(x^2+y^2+6 x-15=0\) and \(x^2+y^2-8 y-10=0\) is
- A \(2\left(x^2+y^2\right)-10 x+5 y=0\)
- B \(2\left(x^2+y^2\right)+10 x-5 y=0\)
- C \(2\left(x^2-y^2\right)+10 x+5 y=0\)
- D \(2\left(x^2-y^2\right)-10 x-5 y=0\)
Answer & Solution
Correct Answer
(A) \(2\left(x^2+y^2\right)-10 x+5 y=0\)
Step-by-step Solution
Detailed explanation
Let the equation of the circle passing through \((0,0)\) is \(x^2+y^2+2 g x+2 f y=0\) ...(i) and the given equations are \(x^2+y^2+6 x-15=0\) ...(ii) \(x^2+y^2-8 y-10=0\) ...(iii) Eqs. (i) and (ii) are orthogonal.…
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