AP EAMCET · Maths · Vector Algebra
Let \(\mathbf{A}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}\). If \(\mathbf{B}\) is a vector in \(X Y\) plane such that \((\mathbf{A}+\mathbf{B}) \cdot \mathbf{B}=15\) and \(\mathbf{A} \cdot \mathbf{B}=6\), then \(|\mathbf{B}|\) is
- A \(6\)
- B \(9\)
- C \(15\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(\mathbf{A}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}\) Let \(\mathbf{B}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}\) \(\because(\mathbf{A}+\mathbf{B}) \cdot \mathbf{B}=15\) and \(\mathbf{A} \cdot \mathbf{B}=6\) \(\Rightarrow \mathbf{A} \cdot \mathbf{B}+\mathbf{B} \cdot \mathbf{B}=15\)…
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