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AP EAMCET · Maths · Vector Algebra

Let \(\mathbf{A}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}\). If \(\mathbf{B}\) is a vector in \(X Y\) plane such that \((\mathbf{A}+\mathbf{B}) \cdot \mathbf{B}=15\) and \(\mathbf{A} \cdot \mathbf{B}=6\), then \(|\mathbf{B}|\) is

  1. A \(6\)
  2. B \(9\)
  3. C \(15\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3\)

Step-by-step Solution

Detailed explanation

\(\mathbf{A}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}\) Let \(\mathbf{B}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}\) \(\because(\mathbf{A}+\mathbf{B}) \cdot \mathbf{B}=15\) and \(\mathbf{A} \cdot \mathbf{B}=6\) \(\Rightarrow \mathbf{A} \cdot \mathbf{B}+\mathbf{B} \cdot \mathbf{B}=15\)…