AP EAMCET · Maths · Differential Equations
The differential equation corresponding to the family of circles given by \((x-a)^2+(y-b)^2=4\), where \(a\) and \(b\) are parameters, is
- A \(4 \frac{d^2 y}{d x^2}+9 y=0\)
- B \(4\left(\frac{d^2 y}{d x^2}\right)^2=\left[1+\left(\frac{d y}{d x}\right)^2\right]^3\)
- C \(4 \frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^2=6 y\)
- D \(4\left(\frac{d^2 y}{d x^2}\right)^2+\left[1+\left(\frac{d y}{d x}\right)^2\right]^2=0\)
Answer & Solution
Correct Answer
(B) \(4\left(\frac{d^2 y}{d x^2}\right)^2=\left[1+\left(\frac{d y}{d x}\right)^2\right]^3\)
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Detailed explanation
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