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AP EAMCET · Maths · Binomial Theorem

The constant term in the expansion of \(\left(\frac{x}{2}+\frac{1}{x}+\sqrt{2}\right)^5\) is \(\frac{a \sqrt{2}}{2}\), then \(a=\)

  1. A 7
  2. B 69
  3. C 63
  4. D 65
Verified Solution

Answer & Solution

Correct Answer

(C) 63

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \left(\frac{x}{2}+\frac{1}{x}+\sqrt{2}\right)^5 \\ & \Rightarrow \quad\left(\sqrt{\frac{x}{2}}+\frac{1}{\sqrt{x}}\right)^{10}=\left(\frac{x+\sqrt{2}}{\sqrt{2} x}\right)^{10} \Rightarrow \frac{(x+\sqrt{2})^{10}}{32 x^5} \end{aligned}\) Forms constant term in…