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AP EAMCET · Maths · Binomial Theorem

The coefficient of \(x^2\) in the expansion of \((1+x)^2(8-x)^{-\frac{1}{3}}\) is

  1. A \(\frac{2167}{4032}\)
  2. B \(\frac{2265}{4132}\)
  3. C \(\frac{313}{576}\)
  4. D \(\frac{3691}{6792}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{313}{576}\)

Step-by-step Solution

Detailed explanation

\((1+x)^2 = 1+2x+x^2\) \((8-x)^{-\frac{1}{3}} = 8^{-\frac{1}{3}}(1-\frac{x}{8})^{-\frac{1}{3}} = \frac{1}{2}(1 + (-\frac{1}{3})(-\frac{x}{8}) + \frac{(-\frac{1}{3})(-\frac{1}{3}-1)}{2!}(-\frac{x}{8})^2 + \dots)\)…