AP EAMCET · Maths · Parabola
The co-ordinates of the focus of the parabola \((x+3)^2=2(y-5)\) is
- A \(\left(\frac{-5}{2}, 5\right)\)
- B \(\left(-3, \frac{11}{2}\right)\)
- C \(\left(3, \frac{-11}{2}\right)\)
- D \(\left(0, \frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(-3, \frac{11}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & (x+3)^2=2(y-5) \\ & \therefore \quad \text {Vertex }=(-3,5), a=\frac{1}{2} \\ & \therefore \text {Focus }(s)=\left(-3,5+\frac{1}{2}\right)=\left(-3, \frac{11}{2}\right) \end{aligned}\) Hence, option (b) is correct.
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