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AP EAMCET · Maths · Quadratic Equation

The number of solutions of the equation \(\sqrt{3 x^2+x+5}=x-3\) is

  1. A \(2\)
  2. B \(1\)
  3. C \(0\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0\)

Step-by-step Solution

Detailed explanation

Domain: \(x-3 \ge 0 \implies x \ge 3\) \(3 x^2+x+5=(x-3)^2\) \(3 x^2+x+5=x^2-6x+9\) \(2x^2+7x-4=0\) \(x=\frac{-7 \pm \sqrt{7^2-4(2)(-4)}}{2(2)}\) \(x=\frac{-7 \pm \sqrt{49+32}}{4}\) \(x=\frac{-7 \pm 9}{4}\) \(x_1=\frac{2}{4}=\frac{1}{2}\) \(x_2=\frac{-16}{4}=-4\) Check solutions…