AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
\(\mathrm{AlCl}_3\) is an electron deficient compound but \(\mathrm{AlF}_3\) is not. This is because
- A atomic size of \(\mathrm{F}\) is smaller than \(\mathrm{Cl}\) which makes \(\mathrm{AlF}_3\) more covalent
- B \(\mathrm{AlCl}_3\) is a covalent compound while \(\mathrm{AlF}_3\) is an ionic compound
- C \(\mathrm{AlCl}_3\) exists as dimer but \(\mathrm{AlF}_3\) does not
- D \(\mathrm{Al}\) in \(\mathrm{AlCl}_3\) is in \(s p^3\) hybrid state but \(\mathrm{Al}\) in \(\mathrm{AlF}_3\) is in \(s p^2\) hybrid state
Answer & Solution
Correct Answer
(B) \(\mathrm{AlCl}_3\) is a covalent compound while \(\mathrm{AlF}_3\) is an ionic compound
Step-by-step Solution
Detailed explanation
According to Fajan's rule, larger is the size of anion, more is the covalent character. So, \(\mathrm{AlCl}_3\) is a covalent, while \(\mathrm{AlF}_3\) is ionic, so \(\mathrm{AlCl}_3\) is electron deficient but \(\mathrm{AlF}_3\) is not.
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