AP EAMCET · Chemistry · Structure of Atom
Calculate the energy associated with the second orbit of \(\mathrm{Li}^{+}\)and find it's radius?
- A \(4.905 \times 10^{-19} \mathrm{~J}, 0.0705 \mathrm{~nm}\)
- B \(4.905 \times 10^{-20} \mathrm{~J}, 0.0705 Å\)
- C \(4.905 \times 10^{-17} \mathrm{~J}, 0.0705 Å\)
- D \(4.905 \times 10^{-18} \mathrm{~J}, 0.0705 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(D) \(4.905 \times 10^{-18} \mathrm{~J}, 0.0705 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
Energy associated with second Bohr's orbit is \[ \begin{aligned} E & =-13.6 \mathrm{Z}^2 / n^2 \\ E & =-13.6 \times 3^2 / 2^2 \\ E & =-30.6 \mathrm{eV} \\ & =-30.6 \times 1.6 \times 10^{-19} \\ & =4.905 \times 10^{-18} \mathrm{~J} \end{aligned} \] Radius of second Bohr's orbit…
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