AP EAMCET · Maths · Area Under Curves
The area (in sq units) between the curve \(y^2=8 x\) and its latus rectum is
- A \(\frac{32}{3}\)
- B \(\frac{64}{3}\)
- C \(\frac{16}{3}\)
- D \(\frac{8 \sqrt{2}}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{32}{3}\)
Step-by-step Solution
Detailed explanation
The required area \(=2 \int_0^2 \sqrt{8 x} d x\) \[ =\left.4 \sqrt{2} \frac{2 x^{3 / 2}}{3}\right|_0 ^2=\frac{8 \sqrt{2}}{3}(2 \sqrt{2})=\frac{32}{3} \]
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