AP EAMCET · Maths · Differentiation
If \(y=\sqrt{\cosh x+\sqrt{\cosh x}}\), then \(\frac{d y}{d x}=\)
- A \(\frac{\sinh x\left(2 y^2+2 \cosh x+1\right)}{4 y\left(y^2+\cosh x\right)}\)
- B \(\frac{\sinh x\left(2 y^2-2 \cosh x-1\right)}{4 y\left(y^2-\cosh x\right)}\)
- C \(\frac{\sinh x(1-2 \sqrt{\cosh x})}{4 y \sqrt{\cosh x}}\)
- D \(\frac{\sinh x(1+2 \sqrt{\cosh x})}{4 y \sqrt{\cosh x}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sinh x(1+2 \sqrt{\cosh x})}{4 y \sqrt{\cosh x}}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x} = \frac{1}{2\sqrt{\cosh x+\sqrt{\cosh x}}} \cdot \frac{d}{d x}(\cosh x+\sqrt{\cosh x})\) \(\frac{d y}{d x} = \frac{1}{2y} \cdot \left(\sinh x + \frac{1}{2\sqrt{\cosh x}} \cdot \sinh x\right)\)…
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