AP EAMCET · Maths · Straight Lines
Number of triangle formed by the lines \(x-y+3=0,2 x-y+3=0,3 x-y+2=0\) and \(x+y-3=0\) is
- A 4
- B 6
- C 3
- D 2
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Slope of line \(x-y+3=0\) is 1 . Slope of line \(2 x-y+3=0\) is 2 . Slope of line \(3 x-y+2=0\) is 3 . Slope of line \(x+y-3=0\) is -1 . As the slope of lines are different, there are 4 concurrent lines. Number of triangles formed by these lines \[ ={ }^4 C_3=4 \]
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