AP EAMCET · Maths · Continuity and Differentiability
Let \([t]\) represents the greatest integer not exceeding \(t\) and \(\mathrm{C}=1-2 \mathrm{e}^2\). If the function
\(f(x)=\left\{\begin{array}{cc}
{\left[e^x\right],} & x < 0 \\
a e^x+[x-2], & 0 \leq x < 2 \\
{\left[e^{-x}\right]-C,} & x \geq 2
\end{array}\right.\)
is continuous at \(\mathrm{x}=2\), then \(\mathrm{f}(\mathrm{x})\) is discontinuous at
- A \(\mathrm{x}=1\) only
- B \(x=0\) and \(x=1\)
- C \(x=0\) only
- D \(x=0, x=1\) and \(x=\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{x}=1\) only
Step-by-step Solution
Detailed explanation
\(\because f(x)\) is continuous at \(x=2\) \(\begin{aligned} & \therefore \mathrm{LHL}=f(2) \\ & \Rightarrow a e^2+[2-2]=\left[e^{-2}\right]-\mathrm{C} \\ & \Rightarrow a e^2-1=0-\left(1-2 e^2\right) \Rightarrow a=2 \end{aligned}\)
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