AP EAMCET · Maths · Quadratic Equation
let \(a, b, c\) be real numbers such that \(2 a+3 b+6 c=0\) and \(g(x) \equiv a x^2+b x+c=0\) has atleast one root in the interval \((1,2)\). If a function \(f:[1,2] \rightarrow R\) for which Rolle's mean value theorem holds is such that \(f(x)\) is a primitive of \(g(x)\), then \(f(x)=\)
- A \(x^3-3 x^2+2 x\)
- B \(3 x^3-6 x^2+2 x\)
- C \(12 x^3-14 x^2+3 x\)
- D \(3 x^3-x\)
Answer & Solution
Correct Answer
(A) \(x^3-3 x^2+2 x\)
Step-by-step Solution
Detailed explanation
Given, \(2 a+3 b+6 c=0\)...(i) and \(g(x)=a x^2+b x+c=0\) According to given information, \(\begin{aligned} & f(x)=\int g(x) d x=\int\left(a x^2+b x+c\right) d x \\ & f(x)=\frac{a}{3} x^3+\frac{b}{2} x^2+c x \end{aligned}\)…
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