AP EAMCET · Maths · Matrices
Let \(A=\left[\begin{array}{cc}1 & 2 \\ -2 & 1\end{array}\right]\) and \(B^{-1}=\left[\begin{array}{ll}1 & 1 \\ 0 & 2\end{array}\right]\). If \(\left(A B^{-1}\right)^{-1}=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\), then \(2 b+5 c+10 d=\)
- A \(0\)
- B \(1\)
- C \(-1\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(A B^{-1}=\left[\begin{array}{cc}1 & 2 \\ -2 & 1\end{array}\right]\left[\begin{array}{ll}1 & 1 \\ 0 & 2\end{array}\right]=\left[\begin{array}{cc}1 & 5 \\ -2 & 0\end{array}\right]\) Now, \(\left|A B^{-1}\right|=0-(-10)=10\) and…
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