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AP EAMCET · Maths · Hyperbola

Intersection of two perpendicular tangents to the hyperbola \(\frac{x^2}{4}-\frac{y^2}{2}=1\) lies on the circle \(x^2+y^2=\ldots \ldots \ldots\)

  1. A 2
  2. B 12
  3. C \(\sqrt{2}\)
  4. D \(2 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

Locus of point of intersection of perpendicular tangents to hyperbola \(\frac{x^2}{4}-\frac{y^2}{2}=1\) is the director circle \(x^2+y^2=4-2=2\) Hence, option (a) is correct.