AP EAMCET · Maths · Circle
If \(Q\) is the inverse point of the point \(\mathrm{P}(2,3)\) with respect to the circle \(x^2+y^2-2 x-2 y+1=0\), then the circle with \(\mathrm{PQ}\) as diameter is
- A \(3 x^2+3 y^2-14 x-16 y+37=0\)
- B \(x^2+y^2-4 x-6 y+13=0\)
- C \(5 x^2+5 y^2-16 x-22 y+33=0\)
- D \(2 x^2+2 y^2-3 x-3 y-11=0\)
Answer & Solution
Correct Answer
(C) \(5 x^2+5 y^2-16 x-22 y+33=0\)
Step-by-step Solution
Detailed explanation
Let the co-ordinate of the point \(Q\) is \((h, k)\). Equation of line \(O P\) : \((y-3)=\frac{2}{1}(x-1)\) \(\Rightarrow \quad 2 x-y=1\) ...(1) \(\because(h, k)\) is on the line \(O P\) \(\therefore \quad 2 h-k=1 \Rightarrow k=2 h-1\) So, co-ordinate of \(P\) is \((h, 2 h-1)\).…
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