AP EAMCET · Maths · Permutation Combination
In an examination hall there are ' \(m n\) ' chairs in \(m\) rows and \(n\) columns. The number of ways in which \(m\) students can be seated such that no row is vacant is
- A \(m^n n\) !
- B \(n^m m\) !
- C \(m^m n !\)
- D \(n^n m\) !
Answer & Solution
Correct Answer
(B) \(n^m m\) !
Step-by-step Solution
Detailed explanation
Given that these is ' \(m n\) ' chairs in \(m\) rows and \(n\) columns. \(\therefore\) Number of ways in which one student can seat in Ist column \(=n\) So, similarly \(m\) students can seat in \(n^m\) ways. Since, students can be arranged in \(m\) ! ways, \(\therefore\) Total…
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