AP EAMCET · Maths · Limits
If \(\mathrm{a}>0, \mathrm{~b}>0\) then \(\lim _{n \rightarrow \infty}\left(\frac{a+b^{1 / n}-1}{a}\right)^n=\)
- A \(a^b\)
- B \(b^a\)
- C \(b^{1 / a}\)
- D \(a^{1 / b}\)
Answer & Solution
Correct Answer
(C) \(b^{1 / a}\)
Step-by-step Solution
Detailed explanation
\(y=\lim _{\mathrm{h} \rightarrow \infty}\left|\frac{\mathrm{a}+\mathrm{b}^{\frac{1}{\mathrm{n}}}-1}{\mathrm{a}}\right|\) now, \(\log _e|y|=\lim _{\mathrm{h} \rightarrow \infty} n \log _e\left|\frac{a+b^{\frac{1}{2}}-1}{a}\right|^{\mathrm{n}}\)…
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